TESTfunda - CAT Question of the Day 04-Apr-13

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Testfunda
04-Apr-13
CAT Question of the Day
A cricket team of 11 players lined up in a straight line for a team photograph. The captain was asked to stand in the center of the line-up.
  1. Bharat and Bhavin stood to the right of the captain
  2. Two players stood between Bhagat and Bhairav.
  3. Seven players stood between Bhadrik and Bhanu
  4. Bhavesh stood to the right of Bhuvan
  5. Bhola and Bhumit stood either side of Bhagat
  6. Bhavik and Bhumit stood to the left of the captain
  7. Six players stood between Bhavin and Bhagat
  8. Two players stood between Bhagat and Bhavik
If P(M) is the position of the player with name M such that the leftmost person has P(A) = 1 [A is the leftmost person] and the rightmost person has P(B) = 11 [B is the rightmost person] , then which of the following is true?
OPTIONS
 
 1)P(Bhuvan) + P(Bharat) + P(Bhavesh) = 21
 2)P(Bhavik) + P(Bhagat) + P(Bhola) + P(Bhumit) = 19
 3)P(Bhuvan) + P(Bhairav) is a prime number and P(Bhuvan) is also a prime number
 4)P(Bhuvan) + P(Bhavin) + [2 × P(Bhavik)] = [3 × P(Bhagat)] + P(Bhairav)
Tip of the Day
Working with inequalities is similar to working with equalities, except for the fact that when both the sides of the inequality are multiplied or divided by a negative number, the inequality gets reversed.
Last year's Question of the day (03-Apr-12)
In the following question, four out of five pairs have a similar relationship. Select a dissimilar pair among the five pairs given.
OPTIONS
 
 1)Bombic: Silkworms
 2)Brumal: Winter
 3)Caballine: Horses
 4)A capella: Singing
 5)Gregal: Geese
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